6x^2-96^2=0

Solution for 6x^2-96^2=0 equation:

6x^2-96^2=0

We add all the numbers together, and all the variables

6x^2-9216=0

a = 6; b = 0; c = -9216;
Δ = b2-4ac
Δ = 02-4·6·(-9216)
Δ = 221184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{221184}=\sqrt{36864*6}=\sqrt{36864}*\sqrt{6}=192\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-192\sqrt{6}}{2*6}=\frac{0-192\sqrt{6}}{12}
=-\frac{192\sqrt{6}}{12}
=-16\sqrt{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+192\sqrt{6}}{2*6}=\frac{0+192\sqrt{6}}{12}
=\frac{192\sqrt{6}}{12}
=16\sqrt{6}
$